5/(4-3z)=z

Solution for 5/(4-3z)=z equation:

5/(4-3z)=z

We move all terms to the left:

5/(4-3z)-(z)=0


Domain of the equation: (4-3z)!=0

We move all terms containing z to the left, all other terms to the right

-3z!=-4

z!=-4/-3

z!=1+1/3

z∈R


We add all the numbers together, and all the variables

5/(-3z+4)-z=0

We add all the numbers together, and all the variables

-1z+5/(-3z+4)=0

We multiply all the terms by the denominator


-1z*(-3z+4)+5=0

We multiply parentheses

3z^2-4z+5=0

a = 3; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·3·5
Δ = -44
Delta is less than zero, so there is no solution for the equation