5/(3z-4)=-3/(1/2z)

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Solution for 5/(3z-4)=-3/(1/2z) equation:


D( z )

3*z-4 = 0

(1/2)*z = 0

3*z-4 = 0

3*z-4 = 0

3*z-4 = 0 // + 4

3*z = 4 // : 3

z = 4/3

(1/2)*z = 0

(1/2)*z = 0

1/2*z = 0 // : 1/2

z = 0

z in (-oo:0) U (0:4/3) U (4/3:+oo)

5/(3*z-4) = -3/((1/2)*z) // + -3/((1/2)*z)

5/(3*z-4)-(-3/((1/2)*z)) = 0

5/(3*z-4)+6*z^-1 = 0

5/(3*z-4)+6/z = 0

(5*z)/(z*(3*z-4))+(6*(3*z-4))/(z*(3*z-4)) = 0

6*(3*z-4)+5*z = 0

23*z-24 = 0

(23*z-24)/(z*(3*z-4)) = 0

(23*z-24)/(z*(3*z-4)) = 0 // * z*(3*z-4)

23*z-24 = 0

23*z-24 = 0 // + 24

23*z = 24 // : 23

z = 24/23

z = 24/23

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