5/(2x+1)-2/(x-4)=0

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Solution for 5/(2x+1)-2/(x-4)=0 equation: 


D( x )

2*x+1 = 0

x-4 = 0

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0 // - 1

2*x = -1 // : 2

x = -1/2

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:-1/2) U (-1/2:4) U (4:+oo)

5/(2*x+1)-(2/(x-4)) = 0

5/(2*x+1)-2*(x-4)^-1 = 0

5/(2*x+1)-2/(x-4) = 0

(5*(x-4))/((2*x+1)*(x-4))+(-2*(2*x+1))/((2*x+1)*(x-4)) = 0

5*(x-4)-2*(2*x+1) = 0

x-22 = 0

(x-22)/((2*x+1)*(x-4)) = 0

(x-22)/((2*x+1)*(x-4)) = 0 // * (2*x+1)*(x-4)

x-22 = 0

x-22 = 0 // + 22

x = 22

x = 22

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