5/(2x)=(9x)/10

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Solution for 5/(2x)=(9x)/10 equation: 


D( x )

2*x = 0

2*x = 0

2*x = 0

2*x = 0 // : 2

x = 0

x in (-oo:0) U (0:+oo)

5/(2*x) = (9*x)/10 // - (9*x)/10

5/(2*x)-((9*x)/10) = 0

(-9/10)*x+5/(2*x) = 0

5/2*x^-1-9/10*x^1 = 0

(5/2*x^0-9/10*x^2)/(x^1) = 0 // * x^2

x^1*(5/2*x^0-9/10*x^2) = 0

x^1

(-9/10)*x^2+5/2 = 0

(-9/10)*x^2+5/2 = 0

DELTA = 0^2-(4*(-9/10)*(5/2))

DELTA = 9

DELTA > 0

x = (9^(1/2)+0)/(2*(-9/10)) or x = (0-9^(1/2))/(2*(-9/10))

x = -5/3 or x = 5/3

x in { -5/3, 5/3} 

x in { -5/3, 5/3 }

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