5/(1-x)=15/(1+x)

Solution for 5/(1-x)=15/(1+x) equation:

5/(1-x)=15/(1+x)

We move all terms to the left:

5/(1-x)-(15/(1+x))=0


Domain of the equation: (1-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-1

x!=-1/-1

x!=1

x∈R



Domain of the equation: (1+x))!=0

We move all terms containing x to the left, all other terms to the right

x)!=-1

x!=-1/1

x!=-1

x∈R


We add all the numbers together, and all the variables

5/(-1x+1)-(15/(x+1))=0

We calculate fractions


5x/((-1x+1)*(x+1)))+(-(15*(-1x+1))/((-1x+1)*(x+1)))=0


We calculate terms in parentheses: -(15*(-1x+1))/((-1x+1)*(x+1))), so:

15*(-1x+1))/((-1x+1)*(x+1))

We multiply all the terms by the denominator


15*(-1x+1))

We multiply parentheses

-15x+

We add all the numbers together, and all the variables

-15x

Back to the equation:

-(-15x)


We get rid of parentheses

5x/((-1x+1)*(x+1)))+(+15x=0

We multiply all the terms by the denominator


5x+15x*((-1x+1)*(x+1)))+(=0