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5.6=x(6-x)
We move all terms to the left:
5.6-(x(6-x))=0
We add all the numbers together, and all the variables
-(x(-1x+6))+5.6=0
We calculate terms in parentheses: -(x(-1x+6)), so:We get rid of parentheses
x(-1x+6)
We multiply parentheses
-1x^2+6x
Back to the equation:
-(-1x^2+6x)
1x^2-6x+5.6=0
We add all the numbers together, and all the variables
x^2-6x+5.6=0
a = 1; b = -6; c = +5.6;
Δ = b2-4ac
Δ = -62-4·1·5.6
Δ = 13.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{13.6}}{2*1}=\frac{6-\sqrt{13.6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{13.6}}{2*1}=\frac{6+\sqrt{13.6}}{2} $
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