5.4(m2)=2(3m+3)

Solution for 5.4(m2)=2(3m+3) equation:

5.4(m2)=2(3m+3)

We move all terms to the left:

5.4(m2)-(2(3m+3))=0

We add all the numbers together, and all the variables

5.4m^2-(2(3m+3))=0


We calculate terms in parentheses: -(2(3m+3)), so:

2(3m+3)

We multiply parentheses

6m+6

Back to the equation:

-(6m+6)


We get rid of parentheses

5.4m^2-6m-6=0

a = 5.4; b = -6; c = -6;
Δ = b2-4ac
Δ = -62-4·5.4·(-6)
Δ = 165.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{165.6}}{2*5.4}=\frac{6-\sqrt{165.6}}{10.8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{165.6}}{2*5.4}=\frac{6+\sqrt{165.6}}{10.8}
$