5-7(2-5x)=2(9x+1)-(13x-57)

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Solution for 5-7(2-5x)=2(9x+1)-(13x-57) equation: 



5-7(2-5x)=2(9x+1)-(13x-57)

We move all terms to the left:

5-7(2-5x)-(2(9x+1)-(13x-57))=0

We add all the numbers together, and all the variables

-7(-5x+2)-(2(9x+1)-(13x-57))+5=0

We multiply parentheses

35x-(2(9x+1)-(13x-57))-14+5=0



We calculate terms in parentheses: -(2(9x+1)-(13x-57)), so:

2(9x+1)-(13x-57)

We multiply parentheses

18x-(13x-57)+2

We get rid of parentheses

18x-13x+57+2

We add all the numbers together, and all the variables

5x+59

Back to the equation:

-(5x+59)



We add all the numbers together, and all the variables

35x-(5x+59)-9=0

We get rid of parentheses

35x-5x-59-9=0

We add all the numbers together, and all the variables

30x-68=0

We move all terms containing x to the left, all other terms to the right

30x=68

x=68/30

x=2+4/15

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