5-4(x+2)=4(2+4x)+5

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Solution for 5-4(x+2)=4(2+4x)+5 equation: 



5-4(x+2)=4(2+4x)+5

We move all terms to the left:

5-4(x+2)-(4(2+4x)+5)=0

We add all the numbers together, and all the variables

-4(x+2)-(4(4x+2)+5)+5=0

We multiply parentheses

-4x-(4(4x+2)+5)-8+5=0



We calculate terms in parentheses: -(4(4x+2)+5), so:

4(4x+2)+5

We multiply parentheses

16x+8+5

We add all the numbers together, and all the variables

16x+13

Back to the equation:

-(16x+13)



We add all the numbers together, and all the variables

-4x-(16x+13)-3=0

We get rid of parentheses

-4x-16x-13-3=0

We add all the numbers together, and all the variables

-20x-16=0

We move all terms containing x to the left, all other terms to the right

-20x=16

x=16/-20

x=-4/5

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