5-4(2x-5)=27x-5+3(7-x)

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Solution for 5-4(2x-5)=27x-5+3(7-x) equation: 



5-4(2x-5)=27x-5+3(7-x)

We move all terms to the left:

5-4(2x-5)-(27x-5+3(7-x))=0

We add all the numbers together, and all the variables

-4(2x-5)-(27x-5+3(-1x+7))+5=0

We multiply parentheses

-8x-(27x-5+3(-1x+7))+20+5=0



We calculate terms in parentheses: -(27x-5+3(-1x+7)), so:

27x-5+3(-1x+7)

determiningTheFunctionDomain
27x+3(-1x+7)-5

We multiply parentheses

27x-3x+21-5

We add all the numbers together, and all the variables

24x+16

Back to the equation:

-(24x+16)



We add all the numbers together, and all the variables

-8x-(24x+16)+25=0

We get rid of parentheses

-8x-24x-16+25=0

We add all the numbers together, and all the variables

-32x+9=0

We move all terms containing x to the left, all other terms to the right

-32x=-9

x=-9/-32

x=9/32

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