5-3/4x=13-1/2x

Solution for 5-3/4x=13-1/2x equation:

5-3/4x=13-1/2x

We move all terms to the left:

5-3/4x-(13-1/2x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-3/4x-(-1/2x+13)+5=0

We get rid of parentheses

-3/4x+1/2x-13+5=0

We calculate fractions


(-6x)/8x^2+4x/8x^2-13+5=0

We add all the numbers together, and all the variables

(-6x)/8x^2+4x/8x^2-8=0

We multiply all the terms by the denominator


(-6x)+4x-8*8x^2=0

We add all the numbers together, and all the variables

4x+(-6x)-8*8x^2=0

Wy multiply elements

-64x^2+4x+(-6x)=0

We get rid of parentheses

-64x^2+4x-6x=0

We add all the numbers together, and all the variables

-64x^2-2x=0

a = -64; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-64)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-64}=\frac{0}{-128}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-64}=\frac{4}{-128}
=-1/32
$