5-3(x-1)+6-4(1-x)=3-4(x+2)

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Solution for 5-3(x-1)+6-4(1-x)=3-4(x+2) equation: 



5-3(x-1)+6-4(1-x)=3-4(x+2)

We move all terms to the left:

5-3(x-1)+6-4(1-x)-(3-4(x+2))=0

We add all the numbers together, and all the variables

-3(x-1)-4(-1x+1)-(3-4(x+2))+5+6=0

We add all the numbers together, and all the variables

-3(x-1)-4(-1x+1)-(3-4(x+2))+11=0

We multiply parentheses

-3x+4x-(3-4(x+2))+3-4+11=0



We calculate terms in parentheses: -(3-4(x+2)), so:

3-4(x+2)

determiningTheFunctionDomain
-4(x+2)+3

We multiply parentheses

-4x-8+3

We add all the numbers together, and all the variables

-4x-5

Back to the equation:

-(-4x-5)



We add all the numbers together, and all the variables

x-(-4x-5)+10=0

We get rid of parentheses

x+4x+5+10=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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