5-3(t-1)=t+4(1-t)+4

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Solution for 5-3(t-1)=t+4(1-t)+4 equation: 



5-3(t-1)=t+4(1-t)+4

We move all terms to the left:

5-3(t-1)-(t+4(1-t)+4)=0

We add all the numbers together, and all the variables

-3(t-1)-(t+4(-1t+1)+4)+5=0

We multiply parentheses

-3t-(t+4(-1t+1)+4)+3+5=0



We calculate terms in parentheses: -(t+4(-1t+1)+4), so:

t+4(-1t+1)+4

We multiply parentheses

t-4t+4+4

We add all the numbers together, and all the variables

-3t+8

Back to the equation:

-(-3t+8)



We add all the numbers together, and all the variables

-3t-(-3t+8)+8=0

We get rid of parentheses

-3t+3t-8+8=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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