5-2x(3x+1)=7(2x+5)=8

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Solution for 5-2x(3x+1)=7(2x+5)=8 equation: 



5-2x(3x+1)=7(2x+5)=8

We move all terms to the left:

5-2x(3x+1)-(7(2x+5))=0

We multiply parentheses

-6x^2-2x-(7(2x+5))+5=0



We calculate terms in parentheses: -(7(2x+5)), so:

7(2x+5)

We multiply parentheses

14x+35

Back to the equation:

-(14x+35)



We get rid of parentheses

-6x^2-2x-14x-35+5=0

We add all the numbers together, and all the variables

-6x^2-16x-30=0

a = -6; b = -16; c = -30;
Δ = b2-4ac
Δ = -162-4·(-6)·(-30)
Δ = -464
Delta is less than zero, so there is no solution for the equation

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