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5-2c=2(c-5)
We move all terms to the left:
5-2c-(2(c-5))=0
We calculate terms in parentheses: -(2(c-5)), so:We get rid of parentheses
2(c-5)
We multiply parentheses
2c-10
Back to the equation:
-(2c-10)
-2c-2c+10+5=0
We add all the numbers together, and all the variables
-4c+15=0
We move all terms containing c to the left, all other terms to the right
-4c=-15
c=-15/-4
c=3+3/4
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