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5-2/5(x+24)=3/4(15+x)
We move all terms to the left:
5-2/5(x+24)-(3/4(15+x))=0
Domain of the equation: 5(x+24)!=0
x∈R
Domain of the equation: 4(15+x))!=0We add all the numbers together, and all the variables
x∈R
-2/5(x+24)-(3/4(x+15))+5=0
We calculate fractions
(-8xx/(5(x+24)*4(x+15)))+(-15xx/(5(x+24)*4(x+15)))+5=0
We calculate terms in parentheses: +(-8xx/(5(x+24)*4(x+15))), so:
-8xx/(5(x+24)*4(x+15))
We multiply all the terms by the denominator
-8xx
Back to the equation:
+(-8xx)
We calculate terms in parentheses: +(-15xx/(5(x+24)*4(x+15))), so:We get rid of parentheses
-15xx/(5(x+24)*4(x+15))
We multiply all the terms by the denominator
-15xx
Back to the equation:
+(-15xx)
-8xx-15xx+5=0
We move all terms containing x to the left, all other terms to the right
-8xx-15xx=-5
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