5-2(z+3)=z-4

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Solution for 5-2(z+3)=z-4 equation: 



5-2(z+3)=z-4

We move all terms to the left:

5-2(z+3)-(z-4)=0

We multiply parentheses

-2z-(z-4)-6+5=0

We get rid of parentheses

-2z-z+4-6+5=0

We add all the numbers together, and all the variables

-3z+3=0

We move all terms containing z to the left, all other terms to the right

-3z=-3

z=-3/-3

z=1

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