5-2(x+3)=2(x+1)-4(x-2)

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Solution for 5-2(x+3)=2(x+1)-4(x-2) equation: 



5-2(x+3)=2(x+1)-4(x-2)

We move all terms to the left:

5-2(x+3)-(2(x+1)-4(x-2))=0

We multiply parentheses

-2x-(2(x+1)-4(x-2))-6+5=0



We calculate terms in parentheses: -(2(x+1)-4(x-2)), so:

2(x+1)-4(x-2)

We multiply parentheses

2x-4x+2+8

We add all the numbers together, and all the variables

-2x+10

Back to the equation:

-(-2x+10)



We add all the numbers together, and all the variables

-2x-(-2x+10)-1=0

We get rid of parentheses

-2x+2x-10-1=0

We add all the numbers together, and all the variables

-11!=0

There is no solution for this equation

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