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5-2(3x-9)=3(x+2)+6x
We move all terms to the left:
5-2(3x-9)-(3(x+2)+6x)=0
We multiply parentheses
-6x-(3(x+2)+6x)+18+5=0
We calculate terms in parentheses: -(3(x+2)+6x), so:We add all the numbers together, and all the variables
3(x+2)+6x
We add all the numbers together, and all the variables
6x+3(x+2)
We multiply parentheses
6x+3x+6
We add all the numbers together, and all the variables
9x+6
Back to the equation:
-(9x+6)
-6x-(9x+6)+23=0
We get rid of parentheses
-6x-9x-6+23=0
We add all the numbers together, and all the variables
-15x+17=0
We move all terms containing x to the left, all other terms to the right
-15x=-17
x=-17/-15
x=1+2/15
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