5-2(3x+1)=2(x-6)+15

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Solution for 5-2(3x+1)=2(x-6)+15 equation: 



5-2(3x+1)=2(x-6)+15

We move all terms to the left:

5-2(3x+1)-(2(x-6)+15)=0

We multiply parentheses

-6x-(2(x-6)+15)-2+5=0



We calculate terms in parentheses: -(2(x-6)+15), so:

2(x-6)+15

We multiply parentheses

2x-12+15

We add all the numbers together, and all the variables

2x+3

Back to the equation:

-(2x+3)



We add all the numbers together, and all the variables

-6x-(2x+3)+3=0

We get rid of parentheses

-6x-2x-3+3=0

We add all the numbers together, and all the variables

-8x=0

x=0/-8

x=0

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