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5-1/6(-x+7)=1+3(2+4x)
We move all terms to the left:
5-1/6(-x+7)-(1+3(2+4x))=0
Domain of the equation: 6(-x+7)!=0We add all the numbers together, and all the variables
x∈R
-1/6(-1x+7)-(1+3(4x+2))+5=0
We multiply all the terms by the denominator
-((1+3(4x+2)))*6(-1x+7)+5*6(-1x+7)-1=0
We calculate terms in parentheses: -((1+3(4x+2)))*6(-1x+7), so:We add all the numbers together, and all the variables
(1+3(4x+2)))*6(-1x+7
We add all the numbers together, and all the variables
-1x+(1+3(4x+2)))*6(+7
Back to the equation:
-(-1x+(1+3(4x+2)))*6(+7)
-(-1x+(1+3(4x+2)))*67+5*6(-1x+7)-1=0
Wy multiply elements
-(-1x+(1+3(4x+2)))*67+30x(--1=0
We use the square of the difference formula
-(-1x+(1+3(4x+2)))*67+30x(+1=0
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