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5-1(1x-4)=3(1x+2)
We move all terms to the left:
5-1(1x-4)-(3(1x+2))=0
We add all the numbers together, and all the variables
-1(x-4)-(3(x+2))+5=0
We calculate terms in parentheses: -(3(x+2)), so:We get rid of parentheses
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
-1(x-4)-3x-6+5=0
We add all the numbers together, and all the variables
-3x-1(x-4)-1=0
We move all terms containing x to the left, all other terms to the right
-3x-1(x-4)=1
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