5-(x-2)=3x-2(x+1)

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Solution for 5-(x-2)=3x-2(x+1) equation: 



5-(x-2)=3x-2(x+1)

We move all terms to the left:

5-(x-2)-(3x-2(x+1))=0

We get rid of parentheses

-x-(3x-2(x+1))+2+5=0



We calculate terms in parentheses: -(3x-2(x+1)), so:

3x-2(x+1)

We multiply parentheses

3x-2x-2

We add all the numbers together, and all the variables

x-2

Back to the equation:

-(x-2)



We add all the numbers together, and all the variables

-1x-(x-2)+7=0

We get rid of parentheses

-1x-x+2+7=0

We add all the numbers together, and all the variables

-2x+9=0

We move all terms containing x to the left, all other terms to the right

-2x=-9

x=-9/-2

x=4+1/2

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