5-(n-4)=3c(n+2)

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Solution for 5-(n-4)=3c(n+2) equation:


Simplifying
5 + -1(n + -4) = 3c(n + 2)

Reorder the terms:
5 + -1(-4 + n) = 3c(n + 2)
5 + (-4 * -1 + n * -1) = 3c(n + 2)
5 + (4 + -1n) = 3c(n + 2)

Combine like terms: 5 + 4 = 9
9 + -1n = 3c(n + 2)

Reorder the terms:
9 + -1n = 3c(2 + n)
9 + -1n = (2 * 3c + n * 3c)
9 + -1n = (6c + 3cn)

Solving
9 + -1n = 6c + 3cn

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3cn' to each side of the equation.
9 + -3cn + -1n = 6c + 3cn + -3cn

Combine like terms: 3cn + -3cn = 0
9 + -3cn + -1n = 6c + 0
9 + -3cn + -1n = 6c

Add '-9' to each side of the equation.
9 + -3cn + -9 + -1n = -9 + 6c

Reorder the terms:
9 + -9 + -3cn + -1n = -9 + 6c

Combine like terms: 9 + -9 = 0
0 + -3cn + -1n = -9 + 6c
-3cn + -1n = -9 + 6c

Reorder the terms:
9 + -6c + -3cn + -1n = -9 + 6c + 9 + -6c

Reorder the terms:
9 + -6c + -3cn + -1n = -9 + 9 + 6c + -6c

Combine like terms: -9 + 9 = 0
9 + -6c + -3cn + -1n = 0 + 6c + -6c
9 + -6c + -3cn + -1n = 6c + -6c

Combine like terms: 6c + -6c = 0
9 + -6c + -3cn + -1n = 0

The solution to this equation could not be determined.

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