5-(n-4)=3+(n+2)

Solution for 5-(n-4)=3+(n+2) equation:

Simplifying
5 + -1(n + -4) = 3 + (n + 2)

Reorder the terms:
5 + -1(-4 + n) = 3 + (n + 2)
5 + (-4 * -1 + n * -1) = 3 + (n + 2)
5 + (4 + -1n) = 3 + (n + 2)

Combine like terms: 5 + 4 = 9
9 + -1n = 3 + (n + 2)

Reorder the terms:
9 + -1n = 3 + (2 + n)

Remove parenthesis around (2 + n)
9 + -1n = 3 + 2 + n

Combine like terms: 3 + 2 = 5
9 + -1n = 5 + n

Solving
9 + -1n = 5 + n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1n' to each side of the equation.
9 + -1n + -1n = 5 + n + -1n

Combine like terms: -1n + -1n = -2n
9 + -2n = 5 + n + -1n

Combine like terms: n + -1n = 0
9 + -2n = 5 + 0
9 + -2n = 5

Add '-9' to each side of the equation.
9 + -9 + -2n = 5 + -9

Combine like terms: 9 + -9 = 0
0 + -2n = 5 + -9
-2n = 5 + -9

Combine like terms: 5 + -9 = -4
-2n = -4

Divide each side by '-2'.
n = 2

Simplifying
n = 2