5-(n-4)=3(n-20)

Solution for 5-(n-4)=3(n-20) equation:

Simplifying
5 + -1(n + -4) = 3(n + -20)

Reorder the terms:
5 + -1(-4 + n) = 3(n + -20)
5 + (-4 * -1 + n * -1) = 3(n + -20)
5 + (4 + -1n) = 3(n + -20)

Combine like terms: 5 + 4 = 9
9 + -1n = 3(n + -20)

Reorder the terms:
9 + -1n = 3(-20 + n)
9 + -1n = (-20 * 3 + n * 3)
9 + -1n = (-60 + 3n)

Solving
9 + -1n = -60 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
9 + -1n + -3n = -60 + 3n + -3n

Combine like terms: -1n + -3n = -4n
9 + -4n = -60 + 3n + -3n

Combine like terms: 3n + -3n = 0
9 + -4n = -60 + 0
9 + -4n = -60

Add '-9' to each side of the equation.
9 + -9 + -4n = -60 + -9

Combine like terms: 9 + -9 = 0
0 + -4n = -60 + -9
-4n = -60 + -9

Combine like terms: -60 + -9 = -69
-4n = -69

Divide each side by '-4'.
n = 17.25

Simplifying
n = 17.25