5-(m-4)=2m+3(m+1)

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Solution for 5-(m-4)=2m+3(m+1) equation: 



5-(m-4)=2m+3(m+1)

We move all terms to the left:

5-(m-4)-(2m+3(m+1))=0

We get rid of parentheses

-m-(2m+3(m+1))+4+5=0



We calculate terms in parentheses: -(2m+3(m+1)), so:

2m+3(m+1)

We multiply parentheses

2m+3m+3

We add all the numbers together, and all the variables

5m+3

Back to the equation:

-(5m+3)



We add all the numbers together, and all the variables

-1m-(5m+3)+9=0

We get rid of parentheses

-1m-5m-3+9=0

We add all the numbers together, and all the variables

-6m+6=0

We move all terms containing m to the left, all other terms to the right

-6m=-6

m=-6/-6

m=1

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