5-(6-2x)=7+(3x-2)

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Solution for 5-(6-2x)=7+(3x-2) equation: 



5-(6-2x)=7+(3x-2)

We move all terms to the left:

5-(6-2x)-(7+(3x-2))=0

We add all the numbers together, and all the variables

-(-2x+6)-(7+(3x-2))+5=0

We get rid of parentheses

2x-(7+(3x-2))-6+5=0



We calculate terms in parentheses: -(7+(3x-2)), so:

7+(3x-2)

determiningTheFunctionDomain
(3x-2)+7

We get rid of parentheses

3x-2+7

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

2x-(3x+5)-1=0

We get rid of parentheses

2x-3x-5-1=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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