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5-(5v+5)=-4(1+3v)
We move all terms to the left:
5-(5v+5)-(-4(1+3v))=0
We add all the numbers together, and all the variables
-(5v+5)-(-4(3v+1))+5=0
We get rid of parentheses
-5v-(-4(3v+1))-5+5=0
We calculate terms in parentheses: -(-4(3v+1)), so:We add all the numbers together, and all the variables
-4(3v+1)
We multiply parentheses
-12v-4
Back to the equation:
-(-12v-4)
-5v-(-12v-4)=0
We get rid of parentheses
-5v+12v+4=0
We add all the numbers together, and all the variables
7v+4=0
We move all terms containing v to the left, all other terms to the right
7v=-4
v=-4/7
v=-4/7
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