5-(4x-7)+11x-22=6(x+3)-8(2x+12)

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Solution for 5-(4x-7)+11x-22=6(x+3)-8(2x+12) equation: 



5-(4x-7)+11x-22=6(x+3)-8(2x+12)

We move all terms to the left:

5-(4x-7)+11x-22-(6(x+3)-8(2x+12))=0

We add all the numbers together, and all the variables

11x-(4x-7)-(6(x+3)-8(2x+12))-17=0

We get rid of parentheses

11x-4x-(6(x+3)-8(2x+12))+7-17=0



We calculate terms in parentheses: -(6(x+3)-8(2x+12)), so:

6(x+3)-8(2x+12)

We multiply parentheses

6x-16x+18-96

We add all the numbers together, and all the variables

-10x-78

Back to the equation:

-(-10x-78)



We add all the numbers together, and all the variables

7x-(-10x-78)-10=0

We get rid of parentheses

7x+10x+78-10=0

We add all the numbers together, and all the variables

17x+68=0

We move all terms containing x to the left, all other terms to the right

17x=-68

x=-68/17

x=-4

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