5-(3w-4)+4=14-2(w+1)

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Solution for 5-(3w-4)+4=14-2(w+1) equation: 



5-(3w-4)+4=14-2(w+1)

We move all terms to the left:

5-(3w-4)+4-(14-2(w+1))=0

We add all the numbers together, and all the variables

-(3w-4)-(14-2(w+1))+9=0

We get rid of parentheses

-3w-(14-2(w+1))+4+9=0



We calculate terms in parentheses: -(14-2(w+1)), so:

14-2(w+1)

determiningTheFunctionDomain
-2(w+1)+14

We multiply parentheses

-2w-2+14

We add all the numbers together, and all the variables

-2w+12

Back to the equation:

-(-2w+12)



We add all the numbers together, and all the variables

-3w-(-2w+12)+13=0

We get rid of parentheses

-3w+2w-12+13=0

We add all the numbers together, and all the variables

-1w+1=0

We move all terms containing w to the left, all other terms to the right

-w=-1

w=-1/-1

w=1

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