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5-(2x-2)=-(-3x+5)-x
We move all terms to the left:
5-(2x-2)-(-(-3x+5)-x)=0
We get rid of parentheses
-2x-(-(-3x+5)-x)+2+5=0
We calculate terms in parentheses: -(-(-3x+5)-x), so:We add all the numbers together, and all the variables
-(-3x+5)-x
We add all the numbers together, and all the variables
-1x-(-3x+5)
We get rid of parentheses
-1x+3x-5
We add all the numbers together, and all the variables
2x-5
Back to the equation:
-(2x-5)
-2x-(2x-5)+7=0
We get rid of parentheses
-2x-2x+5+7=0
We add all the numbers together, and all the variables
-4x+12=0
We move all terms containing x to the left, all other terms to the right
-4x=-12
x=-12/-4
x=+3
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