5+4/7(22+3x)=41

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Solution for 5+4/7(22+3x)=41 equation: 



5+4/7(22+3x)=41

We move all terms to the left:

5+4/7(22+3x)-(41)=0



Domain of the equation: 7(22+3x)!=0

x∈R



We add all the numbers together, and all the variables

4/7(3x+22)+5-41=0

We add all the numbers together, and all the variables

4/7(3x+22)-36=0

We multiply all the terms by the denominator


-36*7(3x+22)+4=0

Wy multiply elements

-252x(3+4=0

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