5+4(5x-5)=6-5(2x+1)

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Solution for 5+4(5x-5)=6-5(2x+1) equation: 



5+4(5x-5)=6-5(2x+1)

We move all terms to the left:

5+4(5x-5)-(6-5(2x+1))=0

We multiply parentheses

20x-(6-5(2x+1))-20+5=0



We calculate terms in parentheses: -(6-5(2x+1)), so:

6-5(2x+1)

determiningTheFunctionDomain
-5(2x+1)+6

We multiply parentheses

-10x-5+6

We add all the numbers together, and all the variables

-10x+1

Back to the equation:

-(-10x+1)



We add all the numbers together, and all the variables

20x-(-10x+1)-15=0

We get rid of parentheses

20x+10x-1-15=0

We add all the numbers together, and all the variables

30x-16=0

We move all terms containing x to the left, all other terms to the right

30x=16

x=16/30

x=8/15

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