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5+3x+7x-2=3(2x+1)
We move all terms to the left:
5+3x+7x-2-(3(2x+1))=0
We add all the numbers together, and all the variables
10x-(3(2x+1))+3=0
We calculate terms in parentheses: -(3(2x+1)), so:We get rid of parentheses
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
10x-6x-3+3=0
We add all the numbers together, and all the variables
4x=0
x=0/4
x=0
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