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5+3=2-2(x+3)
We move all terms to the left:
5+3-(2-2(x+3))=0
We add all the numbers together, and all the variables
-(2-2(x+3))+8=0
We calculate terms in parentheses: -(2-2(x+3)), so:We get rid of parentheses
2-2(x+3)
determiningTheFunctionDomain -2(x+3)+2
We multiply parentheses
-2x-6+2
We add all the numbers together, and all the variables
-2x-4
Back to the equation:
-(-2x-4)
2x+4+8=0
We add all the numbers together, and all the variables
2x+12=0
We move all terms containing x to the left, all other terms to the right
2x=-12
x=-12/2
x=-6
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