5+3+(2z-3)+8+10+(z+1)=39

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Solution for 5+3+(2z-3)+8+10+(z+1)=39 equation: 



5+3+(2z-3)+8+10+(z+1)=39

We move all terms to the left:

5+3+(2z-3)+8+10+(z+1)-(39)=0

We add all the numbers together, and all the variables

(2z-3)+(z+1)-13=0

We get rid of parentheses

2z+z-3+1-13=0

We add all the numbers together, and all the variables

3z-15=0

We move all terms containing z to the left, all other terms to the right

3z=15

z=15/3

z=5

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