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5+3(x-7)=2(x-3)
We move all terms to the left:
5+3(x-7)-(2(x-3))=0
We multiply parentheses
3x-(2(x-3))-21+5=0
We calculate terms in parentheses: -(2(x-3)), so:We add all the numbers together, and all the variables
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
3x-(2x-6)-16=0
We get rid of parentheses
3x-2x+6-16=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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