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5+3(x-1)=x+2(x+1)
We move all terms to the left:
5+3(x-1)-(x+2(x+1))=0
We multiply parentheses
3x-(x+2(x+1))-3+5=0
We calculate terms in parentheses: -(x+2(x+1)), so:We add all the numbers together, and all the variables
x+2(x+1)
We multiply parentheses
x+2x+2
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
3x-(3x+2)+2=0
We get rid of parentheses
3x-3x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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