5+3(4j-2)=5(1+j)+1

Solution for 5+3(4j-2)=5(1+j)+1 equation:

Simplifying
5 + 3(4j + -2) = 5(1 + j) + 1

Reorder the terms:
5 + 3(-2 + 4j) = 5(1 + j) + 1
5 + (-2 * 3 + 4j * 3) = 5(1 + j) + 1
5 + (-6 + 12j) = 5(1 + j) + 1

Combine like terms: 5 + -6 = -1
-1 + 12j = 5(1 + j) + 1
-1 + 12j = (1 * 5 + j * 5) + 1
-1 + 12j = (5 + 5j) + 1

Reorder the terms:
-1 + 12j = 5 + 1 + 5j

Combine like terms: 5 + 1 = 6
-1 + 12j = 6 + 5j

Solving
-1 + 12j = 6 + 5j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-5j' to each side of the equation.
-1 + 12j + -5j = 6 + 5j + -5j

Combine like terms: 12j + -5j = 7j
-1 + 7j = 6 + 5j + -5j

Combine like terms: 5j + -5j = 0
-1 + 7j = 6 + 0
-1 + 7j = 6

Add '1' to each side of the equation.
-1 + 1 + 7j = 6 + 1

Combine like terms: -1 + 1 = 0
0 + 7j = 6 + 1
7j = 6 + 1

Combine like terms: 6 + 1 = 7
7j = 7

Divide each side by '7'.
j = 1

Simplifying
j = 1