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5+3(3x-4)=4(2+x)
We move all terms to the left:
5+3(3x-4)-(4(2+x))=0
We add all the numbers together, and all the variables
3(3x-4)-(4(x+2))+5=0
We multiply parentheses
9x-(4(x+2))-12+5=0
We calculate terms in parentheses: -(4(x+2)), so:We add all the numbers together, and all the variables
4(x+2)
We multiply parentheses
4x+8
Back to the equation:
-(4x+8)
9x-(4x+8)-7=0
We get rid of parentheses
9x-4x-8-7=0
We add all the numbers together, and all the variables
5x-15=0
We move all terms containing x to the left, all other terms to the right
5x=15
x=15/5
x=3
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