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5+3(1+2(2x-3))=6(x+5)
We move all terms to the left:
5+3(1+2(2x-3))-(6(x+5))=0
We calculate terms in parentheses: -(6(x+5)), so:We get rid of parentheses
6(x+5)
We multiply parentheses
6x+30
Back to the equation:
-(6x+30)
3(1+2(2x-3))-6x-30+5=0
We add all the numbers together, and all the variables
-6x+3(1+2(2x-3))-25=0
We move all terms containing x to the left, all other terms to the right
-6x+3(1+2(2x-3))=25
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