5+2x=4(2x+2)-7(x-2)

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Solution for 5+2x=4(2x+2)-7(x-2) equation: 



5+2x=4(2x+2)-7(x-2)

We move all terms to the left:

5+2x-(4(2x+2)-7(x-2))=0



We calculate terms in parentheses: -(4(2x+2)-7(x-2)), so:

4(2x+2)-7(x-2)

We multiply parentheses

8x-7x+8+14

We add all the numbers together, and all the variables

x+22

Back to the equation:

-(x+22)



We get rid of parentheses

2x-x-22+5=0

We add all the numbers together, and all the variables

x-17=0

We move all terms containing x to the left, all other terms to the right

x=17

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