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5+2x=-4x(-x+3)-25
We move all terms to the left:
5+2x-(-4x(-x+3)-25)=0
We add all the numbers together, and all the variables
2x-(-4x(-1x+3)-25)+5=0
We calculate terms in parentheses: -(-4x(-1x+3)-25), so:We get rid of parentheses
-4x(-1x+3)-25
We multiply parentheses
4x^2-12x-25
Back to the equation:
-(4x^2-12x-25)
-4x^2+2x+12x+25+5=0
We add all the numbers together, and all the variables
-4x^2+14x+30=0
a = -4; b = 14; c = +30;
Δ = b2-4ac
Δ = 142-4·(-4)·30
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*-4}=\frac{-40}{-8} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*-4}=\frac{12}{-8} =-1+1/2 $
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