5+2k(k+4)=5(k-3)+10

Solution for 5+2k(k+4)=5(k-3)+10 equation:

5+2k(k+4)=5(k-3)+10

We move all terms to the left:

5+2k(k+4)-(5(k-3)+10)=0

We multiply parentheses

2k^2+8k-(5(k-3)+10)+5=0


We calculate terms in parentheses: -(5(k-3)+10), so:

5(k-3)+10

We multiply parentheses

5k-15+10

We add all the numbers together, and all the variables

5k-5

Back to the equation:

-(5k-5)


We get rid of parentheses

2k^2+8k-5k+5+5=0

We add all the numbers together, and all the variables

2k^2+3k+10=0

a = 2; b = 3; c = +10;
Δ = b2-4ac
Δ = 32-4·2·10
Δ = -71
Delta is less than zero, so there is no solution for the equation