5+2(n+4)=5(n-3)+10

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Solution for 5+2(n+4)=5(n-3)+10 equation: 



5+2(n+4)=5(n-3)+10

We move all terms to the left:

5+2(n+4)-(5(n-3)+10)=0

We multiply parentheses

2n-(5(n-3)+10)+8+5=0



We calculate terms in parentheses: -(5(n-3)+10), so:

5(n-3)+10

We multiply parentheses

5n-15+10

We add all the numbers together, and all the variables

5n-5

Back to the equation:

-(5n-5)



We add all the numbers together, and all the variables

2n-(5n-5)+13=0

We get rid of parentheses

2n-5n+5+13=0

We add all the numbers together, and all the variables

-3n+18=0

We move all terms containing n to the left, all other terms to the right

-3n=-18

n=-18/-3

n=+6

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