5+2(3j-2)=4(1+j)

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Solution for 5+2(3j-2)=4(1+j) equation: 



5+2(3j-2)=4(1+j)

We move all terms to the left:

5+2(3j-2)-(4(1+j))=0

We add all the numbers together, and all the variables

2(3j-2)-(4(j+1))+5=0

We multiply parentheses

6j-(4(j+1))-4+5=0



We calculate terms in parentheses: -(4(j+1)), so:

4(j+1)

We multiply parentheses

4j+4

Back to the equation:

-(4j+4)



We add all the numbers together, and all the variables

6j-(4j+4)+1=0

We get rid of parentheses

6j-4j-4+1=0

We add all the numbers together, and all the variables

2j-3=0

We move all terms containing j to the left, all other terms to the right

2j=3

j=3/2

j=1+1/2

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