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5+1/2y=2y-2.5
We move all terms to the left:
5+1/2y-(2y-2.5)=0
Domain of the equation: 2y!=0We get rid of parentheses
y!=0/2
y!=0
y∈R
1/2y-2y+2.5+5=0
We multiply all the terms by the denominator
-2y*2y+(2.5)*2y+5*2y+1=0
We multiply parentheses
-2y*2y+5y+5*2y+1=0
Wy multiply elements
-4y^2+5y+10y+1=0
We add all the numbers together, and all the variables
-4y^2+15y+1=0
a = -4; b = 15; c = +1;
Δ = b2-4ac
Δ = 152-4·(-4)·1
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{241}}{2*-4}=\frac{-15-\sqrt{241}}{-8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{241}}{2*-4}=\frac{-15+\sqrt{241}}{-8} $
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