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5+1/2a=3/5a
We move all terms to the left:
5+1/2a-(3/5a)=0
Domain of the equation: 2a!=0
a!=0/2
a!=0
a∈R
Domain of the equation: 5a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
1/2a-(+3/5a)+5=0
We get rid of parentheses
1/2a-3/5a+5=0
We calculate fractions
5a/10a^2+(-6a)/10a^2+5=0
We multiply all the terms by the denominator
5a+(-6a)+5*10a^2=0
Wy multiply elements
50a^2+5a+(-6a)=0
We get rid of parentheses
50a^2+5a-6a=0
We add all the numbers together, and all the variables
50a^2-1a=0
a = 50; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·50·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*50}=\frac{0}{100} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*50}=\frac{2}{100} =1/50 $
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