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5+(x+3)=5+(3+x)
We move all terms to the left:
5+(x+3)-(5+(3+x))=0
We add all the numbers together, and all the variables
(x+3)-(5+(x+3))+5=0
We get rid of parentheses
x-(5+(x+3))+3+5=0
We calculate terms in parentheses: -(5+(x+3)), so:We add all the numbers together, and all the variables
5+(x+3)
determiningTheFunctionDomain (x+3)+5
We get rid of parentheses
x+3+5
We add all the numbers together, and all the variables
x+8
Back to the equation:
-(x+8)
x-(x+8)+8=0
We get rid of parentheses
x-x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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